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Trigonometrical Equations
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The general solution of $\frac{{\tan \,2x\, - \,\tan \,x}}{{1\, + \,\tan \,x\,\tan \,2x}}\, = \,1$ is
A
$\phi $
B
$n\pi \pm \frac{\pi }{3}$
C
$n\pi + \frac{\pi }{4}$
D
$n\pi + \frac{\pi }{6}\left( {n \in z} \right)$
Solution
$\frac{\tan 2 x-\tan x}{1+\tan x \tan 2 x}=\tan (2 x-x)=1$
${\tan x=1=\tan \frac{\pi}{4}} $
${x=n \pi+\frac{\pi}{4}}$
Standard 11
Mathematics